2x^2+8x^2+4x=-16

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Solution for 2x^2+8x^2+4x=-16 equation: 



2x^2+8x^2+4x=-16

We move all terms to the left:

2x^2+8x^2+4x-(-16)=0

We add all the numbers together, and all the variables

10x^2+4x+16=0

a = 10; b = 4; c = +16;
Δ = b2-4ac
Δ = 42-4·10·16
Δ = -624
Delta is less than zero, so there is no solution for the equation

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